Adding one space after each number

[Baba Katchka]

bleh = 987654

I would like to create a variable from that 9 8 7 6 5 4

what would be the right way? regex? and if so, what is the regex code?

thank you

[User]

Code: Select all

bleh = 987654

msgbox, % RegExReplace(bleh, "(\d)", "$1 ")

[Baba Katchka]

Code: Select all

bleh = 987654

msgbox, % RegExReplace(bleh, "(\d)", "$1 ")

works really well, what do i add so it does it regardless if its a digit or letter? I tried RegExReplace(bleh, "(\d\w)", "$1 ") but it didnt work
thanks

[iPhilip]

Try this:

Code: Select all

bleh = 98abc7654

msgbox, % RegExReplace(bleh, "[a-zA-Z0-9]", "$0 ")

Cheers!

[Baba Katchka]

Try this:

Code: Select all

bleh = 98abc7654

msgbox, % RegExReplace(bleh, "[a-zA-Z0-9]", "$0 ")

Cheers!

I have this, is there a downside to it? "(\w)", "$1 ")

[User]

I have this, is there a downside to it? "(\w)", "$1 ")

you can use the code below too, though I think iPhilip approach is more suitable!

The code below adds one space after any character within the original text, including space character itself!

Code: Select all

bleh := "ABC D `r`n`r`n[(* % `r`n`r`n123 4"

blehSpace := RegExReplace(bleh, ".", "$0 ")

msgbox, % bleh "`n______________`n`n" blehSpace

[iPhilip]

I have this, is there a downside to it? "(\w)", "$1 ")

That would work as well but the \w syntax matches alphanumeric or underscore, which is different than your original requirement:

... it does it regardless if its a digit or letter

Also, note that subpatterns are not necessary in this solution. As shown above, the "\w", "$0 " syntax works, where $0 is the substring that matched the entire pattern.

Cheers!