Better understanding of pseudo-arrays Topic is solved

[john_c]

There are 2 examples here. The 1st works as expected. The 2nd works a bit strange for me - to take the 1st item (foo) it's need to ask for second item (%pseudoArray2%).

Please, give me some explanation about how it works.

This works as expected:

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pseudoArray := strSplit("foo bar baz", " ")
firstItem := pseudoArray.1 ; Access the 1st item in the pseudo-array
msgBox, %firstItem%

This - not:

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inputString = "foo bar baz"
stringSplit, pseudoArray, inputString, " "
; firstItem = %pseudoArray1% ; msgBox will be empty
; firstItem = %pseudoArray2% ; msgBox will be foo
msgBox, %firstItem%

[gregster]

First of all, StrSplit results in an Array, not an PseudoArray (compare docs). You are actually accessing the array with object syntax (an array is an object)

In the second example, you are suffering syntax problems - you are defining inputString as a string including the "s. You can check with msgbox % inputstring

Either do inputString = foo bar baz instead ("legacy" method for backwards compatibility with older AHK versions), or, better inputString := "foo bar baz"
(notice the : ) - then you will put the string foo bar baz as contents of the variable.
The latter ("expression") syntax is the preferred method for variable assigments and rather future-proof for AHK v2, afaik. See https://autohotkey.com/docs/Variables.htm

That said, you are missing the syntax of StringSplit:

Delimiters contains one or more characters (case sensitive), each of which is used to determine where the boundaries between substrings occur in InputVar. Since the delimiter characters are not considered to be part of the substrings themselves, they are never copied into OutputArray.

Thus, you are taking literal " and space as delimiters ( which will be excluded from the resulting strings).

Instead do this: For a space character, better use the built-in AHK variable A_space:

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inputString := "foo bar baz"
msgbox % inputstring
stringSplit, pseudoArray, inputString, %A_Space%
 firstItem = %pseudoArray1% 
; firstItem = %pseudoArray2% 
msgBox, %firstItem%

[john_c]

...

Thank you very much.

The syntax error you mentioned crepted in my code due to my inattention. Very stupid error, I agree.

It's very interesting for me that StrSplit results as object-based array. However, as I understand StringSplit results as pseudo-array?

[gregster]

Yes, StringSplit results in a pseudo-array. That has historical reasons (and has been kept for backwards compatibility).
The function version StrSplit() is much newer. The "old" command "StringSplit" was introduced back in the day when AHK didn't support real arrays (and other objects).

[john_c]

...

Very useful, thank you again.

[jeeswg]

Keeping it simple:

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q:: ;StrSplit v. StringSplit
vText := "a,b,c"

oArray := StrSplit(vText, ",")
MsgBox, % oArray.Length() " " oArray.1 " " oArray.2 " " oArray.3

StringSplit, vPseudoArray, vText, % ","
MsgBox, % vPseudoArray0 " " vPseudoArray1 " " vPseudoArray2 " " vPseudoArray3

vIndex := 2
MsgBox, % oArray[vIndex]
MsgBox, % vPseudoArray%vIndex%
return